Will the AFR 357cc heads work well???
#13
Registered
Thread Starter
Originally posted by cstraub69@comcast
Then the CFM needs to be 421.14. If not this will put the blower forcing air through a restriction. "Dirty" air will be a result.
Chris
Then the CFM needs to be 421.14. If not this will put the blower forcing air through a restriction. "Dirty" air will be a result.
Chris
#14
zt , good luck with it , will be waiting for yourfinal report .......mine is done and being dressed with marine parts this minute . haven't seen final dyno numbers or $$$$$ amount yet ......bob !!!
#19
Registered
Join Date: Nov 2000
Location: Continental,United States
Posts: 372
Likes: 0
Received 0 Likes
on
0 Posts
When you double atmospheric pressure ie:14.7 lbs of boost, you @double hp, subtracting out some effeciency factors. He ought to be able to easily make 1200 hp with 13 lbs of boost with a motor that makes 650 NA.
I run 13 lbs of boost with a Procharger and use Canfield 355's, In. flow at .700 is 397, with a .655 lift cam, LSA 114.
I run 13 lbs of boost with a Procharger and use Canfield 355's, In. flow at .700 is 397, with a .655 lift cam, LSA 114.
#20
Registered
Hey guys, it sure is fun jumping on the supercharger threads isn't it?
That engine should easily make 650 HP naturally aspirated. To know how much boost you need, you have to know what the intake air temperature will be after the intercooler, which means you have to know the cooling effectiveness of the core. I don't know the cooling effectiveness of the core in this case, but I can guarantee you will need more than 13 psi to make 1200 HP.
How do I know? Let's assume that the intercooler is 100% effective and the supercharged air is the same temperature as ambient air (impossible but bear with me). Let's also assume that it costs no HP to spin the twin blowers (also impossible).
The density ratio would then be:
(14.7 + 13)/14.7 = 1.88
The new HP level would be:
650 X 1.88 = 1222 HP
That's the best theoretical (and impossible) HP you could get. But since the intake air temperature will be hotter than ambient air, the true air density ratio might only be 1.75. And you have to deduct the power taken off the crank to spin the blowers. So the actual HP might be:
(650 X 1.75) - 40 = 1100 HP
As I said, we don't know the cooling effectiveness, but my guess is you would need 14.7 psi and 90% cooling effectiveness to reach 1200 HP with a 650 HP base engine. You can't beat the Ideal gas law!
That engine should easily make 650 HP naturally aspirated. To know how much boost you need, you have to know what the intake air temperature will be after the intercooler, which means you have to know the cooling effectiveness of the core. I don't know the cooling effectiveness of the core in this case, but I can guarantee you will need more than 13 psi to make 1200 HP.
How do I know? Let's assume that the intercooler is 100% effective and the supercharged air is the same temperature as ambient air (impossible but bear with me). Let's also assume that it costs no HP to spin the twin blowers (also impossible).
The density ratio would then be:
(14.7 + 13)/14.7 = 1.88
The new HP level would be:
650 X 1.88 = 1222 HP
That's the best theoretical (and impossible) HP you could get. But since the intake air temperature will be hotter than ambient air, the true air density ratio might only be 1.75. And you have to deduct the power taken off the crank to spin the blowers. So the actual HP might be:
(650 X 1.75) - 40 = 1100 HP
As I said, we don't know the cooling effectiveness, but my guess is you would need 14.7 psi and 90% cooling effectiveness to reach 1200 HP with a 650 HP base engine. You can't beat the Ideal gas law!