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WeaponX 11-17-2006 05:14 PM

Re: Cat Length question
 

Originally Posted by CigDaze
I don't know where the 2.5" is coming from, whether it's the tips of the sponsons or the transom which would affect the tunnel and airfoil, but either way we're talking about a difference of 0.5%. Say it is in the tunnel area, lift and drag behave linearly with surface area as defined by L (or D)=1/2 * rho * V^2 * S * Cl (or Cd), where rho=density, V=velocity in fps, S=planer area in sqft, and Cl=coefficient of lift (or drag). Again, 0.5% differences...maybe.

After running a quick CFD comparison, I see no appreciable difference.

What does all this have to do with a treadmill???? :D

CigDaze 11-17-2006 05:23 PM

Re: Cat Length question
 

Originally Posted by 3600cat
What does all this have to do with a treadmill???? :D

:D
If boat A is 2.5" shorter than boat B and they're traveling in exactly opposite directions on a head-on collision course while on a section of the Mississippi River with a 10 mph current and both of their GPS's indicate 100 mph, what is their closing speed with regards to one another? What would each water pitot speedometer read. assuming they're accurate? :evilb:

SHARKEY-IMAGES 11-17-2006 09:03 PM

Re: Cat Length question
 

Originally Posted by Steve Miklos
Closing speed 200 MPH

Speedo 1 =90
speed0 2 =110

Do I win?

I must of missed the part where they said you were in 1 boat and BS was in the other...... :confused:
:eek: :evilb: :evilb: :D :drink:

Cash Bar 11-17-2006 10:51 PM

Re: Cat Length question
 
BS is definitely the one in the wrong lane..... :eek: :rolleyes:


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