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compresion ratio
What is the correct formula to calculate compression ratio. Reason for asking is that I have a 502 that is being bored .030. Won't that increase compression if I don't purchase a lower domed piston? The block is being decked for straightness as well.
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The more cylinder volume at TDC the less compression
you have but at .030 over it would not be significant |
EXCALABUR when you bore an engine you are increasing the cylinder volume and then compressing that larger volume into the same head volume -- thus you efectively increased the compression ratio. I don't know how much of an increase you will get since it depends on the bore diameter.
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voodoo,
I dont think you will see much of a difference. My formulas are at home. There are web sites that will do the calculation for you. Do a search on the board for past links or search on the net.. I know someone mentioned this in the past. Dont worry about changing the dome on the piston, it will be a small change and wont impact your operation. If you want a close guesstimate. Take the bore and stroke and figure your volume then add the overbore dimension, and refigure your volume. If it is 1 or 2cc, I believe it will be somewhere around .1 on your ratio.. If you have trouble and want more info, email me and I will look for the formula at home this weekend.. Dick |
502 bore = 4.470" Stroke = 4"
swept volume= (pi)*(2.235squared)*4.00=62.76cu.inches .030 over (4.500") swept volume= (pi)*(2.250squared)*4.00=63.605cu.inches Now, we must assume a particular combustion chamber size for reference (the actual size does have an effect on the final values, but since we are going to come up with a relative index, the deviation is insignificant). Let's assume a flattop piston and a flush deck height and a 120cc combustion chamber (7.3 cu.inch). You'll see in a minute why it is okay to make these assumptions... CR = (swept + chamber)/chamber stock: (62.76+7.3)/7.3 = 9.60:1 +.030: (63.605+7.3)/7.3 = 9.71:1 Difference: 9.71/9.60 = 101.14% of the previous CR. If you are currently 7.0:1, you will be 7.08:1 If you are currently 12.5:1, you will be 12.64:1 There's the math. Easy to see that it doesn't make a big deal.. mike |
The formula (IIRC) is on the oreder of:
First get the "displaced" volume [lets call this 'Vscrape'] Code:
[lets call this 'Vblow', ] Lastly you need to know the combustion chamber volume [Vdetonation] The compression ratio is then Code:
Vscrape + Vblow + VdetonationSo for a stock 502 its basically 1020 : 120 which is 8.50:1, that .030 overbore adds ~14.75ccs, and brings you to 8.625 or so... So the answer is: in a lower compression motor you don't have to worry about it. You can thank your 118CC combustion chambers for that... If you had a small chambered head you could end up in more trouble (you could see a full .2 increase...) Now decking the block can cause much more complex issues. When you reduce the 'Vblow/Vdetonation' number you make LARGE changes to compression ratio, and thats the easiest complication. If the block is decked much you will have to at least give some consideration to: - Compression (.060 shaved =15cc= about 10.1:1!) - Valve Clearance (watch your lift!) - Intake manifold alignment** - Valvetrain geometry** The first 2 are rather obvious, the last two will cause ulcers until you diagnose them... Well the intake thing could be obvious in a boat, if it causes a gas leak and its only a small explosion ;) Now don't even think about using my equations, just do what was suggested and use one of the myriad of online calculators :) --Adam |
FWIW I started that post long before mcollin replied, but got busy, doh!
--Adam |
Most piston companies adjust the dome configuration to the overbore so the c/r doesn't change significantly.
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Thanks for all the replies guys!
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What is the "displaced" volume or the "swept" volume that both of you are talking about? Is that the formula for figuring out the volume of a cylinder? This is the volume that will be compressed into the compression chamber? I don't understand why the "static" volume needs to be incorporated into the formula? Couldn't you just add the "head gasket" volume without the "static" volume in the second equation?
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