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Baja Daze
Originally posted by Troutly Well, lets make some assumptions here.....first, lets assume the boat FALLS the total vertical distance of the height of the wave crest (100 ft). And, lets assume the take off angle was +45 degrees. With this in mind, the horizontal distance the boat would travel at a 60 MPH vault would be approx. 317.659 feet...not adjusting for center of mass... :) |
Ya Troutly I came up with 317.656 feet :p :p :p
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Oh see I took into account for the driving rain pushing down on the boat and the dencity of the air :D:D The devil is in the details :D:D
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Originally posted by Troutly Well, lets make some assumptions here.....first, lets assume the boat FALLS the total vertical distance of the height of the wave crest (100 ft). And, lets assume the take off angle was +45 degrees. With this in mind, the horizontal distance the boat would travel at a 60 MPH vault would be approx. 317.659 feet...not adjusting for center of mass... :) Where would you have the drives and tabs set?:D |
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I concur, 317' :)
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Okay, I believe it now.:p
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This must of hurt!
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Holy chit Cord! Wild photos!:eek: :eek: :eek:
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Originally posted by wwwTOPDJcom ZERO But if its was a Apache it would float back to the surface unscathed |
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