So what % Toluene would raise 89 octane fuel to 93 octane?

Robert,

5:1 (20%) Toluene will elevate 89 (R+M)/2, to 93.166 (R+M)/2 octane. The math on determining the ratio is fairly simple. Rather than attach a spreadsheet, I have a conversion sheet that was sent to me for original octane vs. blended octane w/ toluene below. It can be printed and used in the field.
Credit unknown.

Bob

Bob,

Thanks! I guess another question would be what is the minimum octane I would need with 8.75:1 CR, iron heads and 5 lbs of boost? I know it runs fine on 93 octane on the dyno. Don't mean to hijack the thread here .

http://www.blowerdriveservice.com/techcharts.php

Cool! Thanks. Answer = stick with 93 octane. 11.725:1 @ 5 psi.

Your eyes must be better than mine!

I priced mine at a local chem supply house. $217 for 55gal = $3.95 a gallon.

$7.25 a gallon is Insane BIG Daddy , we pay $200.00 a drum and pick up 10 to 12 barrels at a time . Buy a 10.00 box of business cards and open a commercial account at Sherwin Williams under Daytona Painting Co ... they may be qouting you off the street prices.. good luck

I have had good luck with this stuff in motorcycles, both HD and turbocharged sport bikes (5 psi with stock pistons).

Good stuff, can get a good price from Kemco oil.